Which function below is the inverse of f(x) = The quantity of four x minus three, over two.? f−1(x) = two over the quantity of four x minus three f−1(x) = two over the quantity of three minus four x f−1(x) = The quantity of two x minus three, over four f−1(x) = The quantity of two x plus three, over four
b
\[f(x)=\frac{4x-3}{2}\]?
if so, it is definitely not B
@satellite73 yes
ok it is the same as solving say \[\frac{4x-3}{2}=7\]
you know how to solve that?
no lol
oh then you are not going to like this !
darn it
\[\frac{4x-3}{2}=7\] multply by 2 get \[4x-3=14\]
ok
add \(3\) and get \[4x=17\] then divide by 4 to finish with \[x=\frac{17}{4}\]
now we are going to do the same thing with variables you havef \[f(x)=\frac{4x-3}{2}\] lets write it as \[y=\frac{4x-3}{2}\]
then switch x and y (because that is what the inverse does) and get \[x=\frac{4y-3}{2}\] solve for \(y\) the steps are the same as above
\[\frac{4y-3}{2}=x\] multiply by 2 get \[4y-3=2x\]
add 3 get \[4y=2x+3\] then divide by 4 to get \[y=\frac{2x+3}{4}\]
very very confusing but ill try
and that is your inverse \[f^{-1}(x)=\frac{2x+3}{4}\]
it is confusing if you cannot solve \[\frac{4x-3}{2}=7\] but the steps are only three : multiply by 2 add 3 divide by 4
that is what the inverse function \[f^{-1}(x)=\frac{2x+3}{4}\] does
x=−32+2y
i have no clue lol
you lost me there i wrote the steps above, see if you can follow them if not let me know all is written out i did not skip any
x=4.25
@satellite73
yes that is with the numbers now take a look at the same steps with i wrote it with variables
i dont know what to do there
i did it for you follow the steps to the answer
do i plug in the x
follow the post starting with "now we are going to do the same thing with variables"
i have no idea what I do with the steps?
follow them i did it for you
i cant figure it out to save my life
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