Question

Solve: sinx + cosx = 1

Answer 1

\[\sin x+\cos x=1\]
squaring both sides
\[\sin ^2 x+\cos ^2x+2\sin x \cos x=1\]
\[1+\sin 2x=1,\sin 2x=0=\sin n \pi,2x=n \pi,x=\frac{ n \pi }{ 2 }\]
where n is an integer.

Answer 2

wait why square both sides

Answer 3

\[\sin ^2x+\cos ^2x=1\]

Answer 4

\[\sin 2x=2\sin x \cos x\]

Answer 5

so sin x+cosx =sin 2x

Answer 6

could u show me step by step process, i will memorize the identities.

Answer 7

like how did u get from sinx + cosx to sin 2xcos2x??

Answer 8

i know the identity
\[\sin ^2x+\cos ^2x=1\]
sin 2x=2sinx cosx
the idea is to change in one trigonomety ratio only.

Answer 9

ok