What is the equation of the directrix for the conic section shown below?
y^2=-36x
x=4
x=9
y=-6
y=9
I think it is x=4.
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OpenStudy (anonymous):
I need help
OpenStudy (anonymous):
you got yourself a parabola with vertex at the origin \((0,0)\)
OpenStudy (anonymous):
do you know if it opens left, right, up or down?
OpenStudy (maddy1251):
Left. @satellite73
OpenStudy (anonymous):
you need to know that first to find the directrix
right, it opens to the left
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OpenStudy (anonymous):
this looks just like \[y^2=4px\] what is \(p\)?
OpenStudy (maddy1251):
p=1?
OpenStudy (anonymous):
\[4p=-36\\
p=?\]
OpenStudy (maddy1251):
oh! -9
OpenStudy (maddy1251):
My bad, I am sorry.
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OpenStudy (anonymous):
yeah and the fact that you know it has vertex at \((0,0)\) and opens to the left tell you that the directrix is a vertical line 9 units to the right of the vertex
OpenStudy (anonymous):
|dw:1449714017172:dw|
OpenStudy (maddy1251):
@satellite73 y=9 then, since you said vertical?
OpenStudy (anonymous):
since i said it was vertical it is not y equals anything
that would be horizontal
OpenStudy (maddy1251):
OH. Yeah... (duh) I am like half brain dead, I've been doing finals all day. SO, its x=9, then, right?
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