Please Help!! At 20 °C, Li2CO3 (MM = 73.89) has a solubility of 13 g/L in water. What is the Ksp of Li2CO3 at 20 °C?
http://www.chemteam.info/Equilibrium/Calc-Ksp-FromGramSolub.html See if this will help
Those are great explanations, but I need help with what to do with the 20 degrees celsius.
Alright then.
@whpalmer4
okay, the solubility is affected by temperature. However, in this problem, we have data for the solubility at that temperature.
Is there a specific equation that I can go by? Just wondering?
Did you look at this? http://www.chemteam.info/Equilibrium/Calc-Ksp-FromMolSolub.html
The first thing you need to do is write the equation for the dissolution of lithium carbonate in aqueous solution. \[\text{Li}_2\text{CO}_3\text{(s)}\rightarrow 2 \text{Li}^{+}\text{(aq)} +\text{CO}_3^{2-}\text{(aq)}\]
Does This have to do with the ICE chart?
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