Need help on work problem.

Question

briana.img · Answer

attachment

arihangdu · Answer

I'm sorry @briana it beyond my knowledges

briana.img · Answer

@satellite73 hey can you help me out please

sleepyjess · Answer

Hmmm... let me get all of my thoughts out, then see what hapens from there :)

sleepyjess · Answer

Nevermind... this is just making me go around in circles...

sleepyjess · Answer

@Astrophysics

caozeyuan · Answer

lets go step by step

caozeyuan · Answer

from statement 1 we know B+C+R+F=360

briana.img · Answer

mmm yeah!

caozeyuan · Answer

2F=B, 2R=C, ok?

briana.img · Answer

yeah that makes sense

caozeyuan · Answer

1.5R=F, last one

caozeyuan · Answer

4 unknows, 4 eqas. all of them are simple

briana.img · Answer

so you put that all together in an equation?

caozeyuan · Answer

yep, there you go

whpalmer4 · Answer

This is pretty easy.  

$$B + C + F + R = 360$$
We know we have 2x as many B as F, so $$B = 2F$$
We have 2x as many C as R, so $$C = 2R$$and we have 1 1/2 times as many F as R, so $$F = \frac{3}{2}R$$

Now just take the original equation and do all of those substitutions.  For example, the first one might be
$$B+C+F+R=360$$$$2F+C+F+R=360$$etc.  Eventually you will have an equation where R is the only variable, and you can solve that.  Then work backwards.

briana.img · Answer

okay so i would do 2F+C+F+R=360 
find r? 

and then do B+2R+F+R=360

and then keep going, right?

caozeyuan · Answer

no, you throw the last three into the first one, solve it, then move on

whpalmer4 · Answer

No, don't substitute variables that you've eliminated back in:

$$2F + C + F + R = 360$$$$3F + C + R = 360$$Okay, now pick one of your equations that has either F, C, or R on the left side and use it to get rid of another variable.

whpalmer4 · Answer

I would just go straight down the list that I gave you
substitute $2R$ everywhere you see $C$ next
then substitute $\frac{3}{2}R$ every place you see $F$

briana.img · Answer

2R+2R+1.5R=360  ??

whpalmer4 · Answer

$$3F+C+R = 360$$$$3F + (2R) + R = 360$$$$3(\frac{3}{2}F) + 2R + R = 360$$

briana.img · Answer

where did the three come from??

briana.img · Answer

the final equation is the only equation right?

whpalmer4 · Answer

Sorry, I mistyped something!

$$3F + (2R) + R = 360$$Now we substitute $F = \frac{3}{2}R$ in there, but we don't have 1 F, we have 3 F, so it is
$$3(\frac{3}{2}R) + (2R) + R = 360$$which is$$\frac{9}{2}R + 2R + R = 360$$$$\frac{15}{2}R = 360$$can you solve that?