How to integrate e^(e^x). I used taylor series to find the approximation. Is there another way of solving it? Thx

Question

md152727 · Answer

http://integrals.wolfram.com/index.jsp?expr=e%5E%28e%5Ex%29&random=false

anonymous · Answer

Thanks mate but what do they mean by E?

anonymous · Answer

And how did it arrive to that answer

kainui · Answer

The only way I can see to integrate it is this way:

$$e^y = \sum_{n=0}^\infty \frac{y^n}{n!}$$
$$e^{e^x} = \sum_{n=0}^\infty \frac{e^{xn}}{n!}$$

now you can integrate term by term of this power series.

anonymous · Answer

Could you please show me the whole solution?

kainui · Answer

Nah, there's not really unless you want to define a new function.