Question

I have done this problem about ten times, and all I ever get is is 9.7 and according to my wonderful answer sheet at the back, it is not 9.7, unfortunately.

Where am I going wrong?

http://prntscr.com/9cg6j0

Answer 1

@UsukiDoll Save me?

Answer 2

strange... if t is the days in the year
is the formula
\[\huge f(t) = 11+2.2\sin((\frac{2 \pi}{365})t-1.25)\]

Answer 3

i got 11.5 but i have no idea what i did hahaha

Answer 4

yay I love it when OS carps out on me. smh

Answer 5

so if the problem mentions 12th day then t = 12

Answer 6

That's what I thought. So I've been going with

11 + 2.2sin((2pi/365)12 - 1.25)

Answer 7

From what my notes tell me, it's basically just a plug in and viola! A correct answer.

Answer 8

whats the answer supposed to be?
i get 9.1

Answer 9

It is 9.1 - or so I'm told. But I don't get how you got 9.1

Answer 10

Ooo the grammar in that post. I'm tired.

Answer 11

i just plugged in t=12

Answer 12

check your calculator, it should be set to "radians" not degree

Answer 13

That's what I did, but I got 9.7

Answer 14

When I switch to RAD, I'm looking at 10.20

Answer 15

i think you are messing up with the brackets when you enter it in your calculator

Answer 16

Oh there we go. Yeah, decided to use script calculator thanks! Now getting 9.1

Answer 17

\[\huge f(12) = 11+2.2\sin((\frac{2 \pi}{365})12-1.25)\]
UGH OS COME ON!
sorry OS IS TRIPPING ON ME
\[\huge f(12) = 11+2.2\sin((0.017214)(12)-1.25)\]
\[\huge f(12) = 11+2.2\sin((0.2065-1.25)\]
\[\huge f(12) = 11+2.2\sin(-1.043429)\]
\[\huge f(12) = 11+2.2(-0.864134)\]
\[\huge f(12) = 11-1.9010969\]
\[\huge f(12) =9.08903 \] which rounds up approximately 9.1
and i was in radians.

Answer 18

I don't have all the decimals which is why I'm a bit off, but it does come up to 9.1 or close to 9.1

Answer 19

9.0989024570422309013004511953127 whewwww xxxxx