Question

SOLID MENSURATION QUESTION (Need help ASAP)

I've been trying different kinds of method but it's not even helping

A piece of wire length 52m is cut into two parts. Each part is then bent to form a square. It is found that the combined area of the two squares is 109 sq. m. Find the measures of the sides of the two squares.

Need help ASAP :(

tA = ((52 - Ps1)/4 )^2 + ((52 - Ps2)/4)^2

i tried this but it didnt work

Answer 1

if you cut the wire into two lengths x & y

then you know that x+y = 52

the squares have sides x/4 and y/4

so the area of the squares are (x/4)^2 and (y/4)^2

so (x/4)^2 +(y/4)^2 = 109

I have solved by graphing (plot both equations and find intersection points), but not yet solved analytically

Answer 2

@MrNood Soo how can i solve the sides? the x and y's... it seems impossible if thats the given equation.

Answer 3

you have 2 equations
x+y =52
(x/4)^2 +(y/4)^2 = 109

from the first y= (52-x)
substitiute that into the second equation

you will get a quadratic in x

solve for x
then solve for y in the first equation.

The answer is x/4 and y/4 for th esquare side lenghts

Answer 4

Oh i see i get it now

Answer 5

let me try it first

Answer 6

note - the quadratic has TWO real solutions

you can choose EITHER of them since we don't care whch 'end' of the wire is which

Answer 7

Thank you so much @MrNood XD

Answer 8

np.

and oyur answer is?....

Answer 9

first square is 10m per sides. with the perimeter of 40m
second square is 3m per sides with the perimeter of 12m

then total perimeter is 40 + 12 = 52

and area is 10^2 + 3^2 = 100 + 9 = 109m^2

i finally get it now thanks a lot

Answer 10

well done

good to see someone stick it out through some complicated calculation!

Answer 11

took me 1 week to understand the question properly... i used this site as my last resort. glad i finally understand this. lol thanks again