write an equation in point-slope form for the line through the given point with the given slope.(-3, -5); m = -2/5
you know the 'point slope' form is y=mx+b and you are told m so the equation is y= -2/5 x +b but you also know that when x= -3 then y = -5 so -5 = -2/5 (-3) + b so oyu can work out b and there is your answer
point slope form y-y1=m(x-x1) where m is slope and (x1,y1) is point.
A line with slope m, that passes through and point \((x_1, y_1)\) has the point-slope equation: \(y - y_1 = m(x - x_1)\)
Thanks! Fastest responses I've ever received lol XD
In your case, you are given \(slope = m = - \dfrac{2}{5} \), and point \((-3, -5)\). Just substitute these values into the equation above. Keep in mind that you need to subtract the x-coordinate and the y-coordinate of the point. Both your x- and y-coordinates are negative, so be careful with the signs.
@MrNood You wrote "you know the 'point slope' form is y=mx+b" ... That is actually the slope-intercept form, not the point-slope form.
soz - yes . I'll read the question properly next time! :-)
So, the answer would be y - 5 = -2/5 (x - 3)?
No. That is not the answer. You did plug int he slope correctly, but above I mentioned that the coordinates of the point are both negative numbers and you need to be careful because you are subtracting two negative numbers.
Always start with the equation or formula. Write it down. It will help you with the problem, but it will also help you memorize the formula or equation.
We start with the point-slope equation: \(y-y_1=m(x-x_1) \) Now we replace \(x_1\) with -3, \(y_1\) with -5, and m with \(- \dfrac{2}{5} \) \(y-(-5)=-\dfrac{2}{5}(x-(-3)) \) Notice that all I did was the substitutions for x1, y1 and m. Now simplify the subtractions of negative numbers. Remember that subtracting a negative number is adding. \(y +5=-\dfrac{2}{5}(x+3) \)
OOoohhhhh. Okie. I see it now...>XD
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