Question

How on earth do you solve (e^x)(e^x+1)=1

Answer 1

uhhhh

Answer 2

is it \[(e^x)(e^{x+1})=1\] ?

Answer 3

if yes then use the exponent rule
when we multiply same bases we should `add` the exponents \[\large\rm x^m \times x^n=x^{m+n}\]

Answer 4

$$e^{-x} = (e)(e^x)$$
$$e^{2x} = e^{-1}$$
$$x = -0.5$$

Answer 5

and then use the fact ln cancel out the e\[\rm \cancel{\ln e}^a = a\]

Answer 6

Yes! Oh, so the two would just combine?

Answer 7

Wait, so if you added x and x+1, then would it just become e^2x+1?

Answer 8

is it e^{x+1} or\[ e^x+1 \] which one is correct

Answer 9

the first one e^{x+1}

Answer 10

alright good and yes then it would be \[\rm e^{2x+1}=1\]

Answer 11

and then just take the ln and solve for x, correct? :)

Answer 12

correct

Answer 13

Okay! Thank you so so much!

Answer 14

np :=))

Answer 15

After solving it, I got -1/2

Answer 16

that's correct!! good work