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Mathematics 16 Online
OpenStudy (hope210):

will medal Solve 2x - 1 < 7 and 5x + 3 < 3. {x | x < 0} {x | x < 4} {x | 0 < x < 4}

OpenStudy (landon34):

@Hope210

OpenStudy (hope210):

okay

OpenStudy (landon34):

Im gonna write this down in my notebook, and Ill try to solve it.

OpenStudy (hope210):

cool thanks

OpenStudy (landon34):

It will be a minute or 2.

OpenStudy (landon34):

you can go do something else while I solve this.

OpenStudy (hope210):

okay bye

OpenStudy (landon34):

@whpalmer4

OpenStudy (landon34):

k im bak

OpenStudy (landon34):

I would recommend you check out https://www.khanacademy.org/

OpenStudy (landon34):

im gonna do something else, bye.

OpenStudy (whpalmer4):

Solve \(2x - 1 < 7\) and \(5x + 3 < 3\) Start with \[2x-1<7\]We want to get \(x\) alone on one side of the inequality sign with everything else on the other. You can do anything you want as long as you do it to both sides. However, if you multiply or divide by a negative number, you must change the direction of the inequality sign. \[2x-1 < 7\]Let's add \(1\) to both sides:\[2x-1+1 < 7 + 1\]\[2x < 8\]Now let's divide both sides by \(2\):\[\frac{2x}{2} < \frac{8}{2}\]\[x<4\] We have determined that our solution is only going to contain values which meet the constraint that \(x<4\). We don't know yet if it means that ALL values of \(x<4\) work. For that, you need to repeat the process on the other inequality, and then look at the combination.

OpenStudy (hope210):

Thank you

OpenStudy (whpalmer4):

@Hope210 what did you get for your final answer?

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