can somebodl help meh!??
What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1?
Sure
umm do i do this in general form??
Yes
**standard form
...
Converting that given equation to "slope-intercept form" would be a good start. That form looks like y=mx+b, where m is the slope and b is the y-intercept. Start with the given equation and solve it for y.
yeah so i did -1=2x-2y over -1 am i on the right pass
2y = 3x - 1 begins with "2y." We don't want 2y; we want just y alone. Starting with 2y = 3x - 1 what should you do to isolate (solve for) y?
The reason I ask you to solve this equation for y is that you will obtain an equation in the form y=mx+b, which will give you the slope of the given line.
Given 2y = 3x - 1 please divide every term by 2. Why?
y = - 2/3 x - -1/3 then I did - 1 = 3/2 * 3 + b
GEEZ I think I'm doing it wrong??
O_o am i doing it right right now?? 2y=-1-3x and then I actually rearenged the form and 2y=-3x-1 ugh..ithink i got -1/2 :/
oops** _2/3
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