Please help! Will give medal and fan. Thank you in advance :) 1. Simplify the expression. -5 + i/2i
1/i = -i So i/2i = i/2 * -i = \(\cfrac{-i^2}{2}\) See that? Then -5 + i/2i = \(-5+\cfrac{-i^2}{2}\) Then \(i^2=-1\) Can you finish it?
Okay. Thank you. I don't think I can honestly, I'm not at all familiar with these problems. I'm very behind in my Algebra class. I don't expect you to give me the answer, but if you could just work with me on it :) that would be great. @ybarrap
You have $$ -5 +\cfrac{i}{2i} $$ Right?
Right
I explained that 1/i = -i, which you can use; however you can also cancel the i's: $$ -5 +\cfrac{\cancel i}{2\cancel i}=-5+\cfrac{1}{2} $$ See that?
This is the easier approach; however, the 1st approach shows how things work if you play with the imaginary number, i. BTW, \(i=\sqrt{-1}\) so \(i^2=-1\), just in case
does any of this make any sense?
Okay. So it's easiest to keep the i's in the equation?
Em, I'm trying to grasp it all lol.
yes, if you cancel them, you can just deal with them like regular old numbers
keep trying, it's fulfilling and exciting
Okay. Lol I'm not so sure about it being exciting, so much as complicated.
did I say that, lol
Yes lol
There was a time when people thought that you could not take a square root of a negative number, then someone decided, not that complicated, just make it the letter "i" and deal with it like an ordinary number and see what happens.
Okay.
So once you've simplified you have $$ -5 + \cfrac{1}{2}=-4\cfrac{1}{2}=-\cfrac{9}{2} $$
Alright
good luck \(:-) \)
Thank you @ybarrap
You're welcome
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