Question

HELP ME!! with math

Answer 1

\[3+\sqrt{2x-3}=x\]

Answer 2

solve the radical equation.

Answer 3

Then I need help with another one too.

Answer 4

It says, find the domain of the square root function. Write the answer in interval notation
\[f(x)=\sqrt{12-4x}\]

Answer 5

@DariusX can you help me with this problem

Answer 6

I don't know if you want it, but I'd be glad to offer my help!

Answer 7

Give it a shot.

Answer 8

Okay, let's start with the first one.

Answer 9

What are you trying to do with the equation? Solve for x?

Answer 10

First subtract 3 from both sides, then square it.

Answer 11

I think it just says solve the radical equation. It doesn't specify much

Answer 12

no that will still leave you with two unlike x terms

Answer 13

@reaganchoi that is smart, total missed that.

Answer 14

closet you can get with that is \[6=x ^{2}-x\]

Answer 15

Oh, wait IDK. I truly need help.

Answer 16

Isn't it 6=x

Answer 17

I have a nerd for a dad. His job is math. If you wait just one sec i'll be right back with his answer

Answer 18

That sounds GREAT!

Answer 19

\[x ^{2}-x\] is equal to x which ends up being x=6

Answer 20

Okay, based on this equation, you must be learning quadratics which I hadn't thought o until my dad and I conferred. Anyway, \[ax ^{2}+bx+c\] sounds like your formula for your solution

Answer 21

That sound about right, I do remember that formula from my last class.

Answer 22

I'm so lost now I thought I had it right... .___.

Answer 23

I know @Adrianna.Gongora I was doing it the same exact way you was but its different.

Answer 24

I think I did it wrong cause there was no parenthesis around the x part

Answer 25

its the way @Seeing.In.Pixels is saying

Answer 26

That is the way its given to me

Answer 27

Glad to help. Shall we move on to the second problem, or do you understand?

Answer 28

No wait, I don't know how to get the problem done. Is it the way @Adrianna.Gongora was saying? or no. I do remember the formula but for some reason I so lost with this problem.

Answer 29

Alrighty then. Let's try this again.\[3+\sqrt{2x-3}=x\]
We know that we want our answer in the form I mentioned before, right? So let's try to do that. the x's need to be together, so start by squaring both sides to make that possible.

Answer 30

So the 3 will need to be subtracted to the other side right.