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Geometry 19 Online
OpenStudy (anonymous):

Can someone help me with these problems? I'm not sure how to do them and I have to turn it in tomorrow.

OpenStudy (anonymous):

sure what problems

OpenStudy (sleepyjess):

Hello! I'm definitely willing to try! What's the first question? ^_^

OpenStudy (alexandervonhumboldt2):

what are your questions?

OpenStudy (anonymous):

OpenStudy (anonymous):

i cant really read the first one

OpenStudy (sleepyjess):

Question, on the first question, reason #2, how do you know it's the definition of midpoint? Point C hasn't been mentioned as the midpoint of line BD

OpenStudy (ram231):

perpendicular is the opposite of parallel. so if parallel is like a parallelogram, and its like a train track. what would perpendicular mean?

OpenStudy (sleepyjess):

I feel like <ACB \(\cong\) <ECD would be in the second spot since that's also a given.

OpenStudy (anonymous):

@sleepyjess I don't know what i'm doing, I tried looking for examples online and i guessed.

OpenStudy (anonymous):

ans easy way to remember perpendicular is: imagine a big lowercase t

OpenStudy (sleepyjess):

Okay, normally all of the "Given"s will be in the first couple of slots

OpenStudy (anonymous):

or cross

OpenStudy (anonymous):

In the second picture, would the Statement #2 be AC BD for definition of perpendicular?

OpenStudy (sleepyjess):

We already used AC perpendicular to BD, perpendicular means there will be right angles somewhere. Where do you think there would be right angles knowing that AC is perpendicular to BD?

OpenStudy (anonymous):

angle c?

OpenStudy (anonymous):

or would it be angle 1 and angle 2

OpenStudy (ram231):

with perpendicular lines, @sleepyjess they don't always have to have right angles in them. just a thought

OpenStudy (sleepyjess):

Perpendicular means that there will be right angles

OpenStudy (ram231):

not how I learned it in school and I am in 11th grade geometry

OpenStudy (ram231):

and my twin is in AP pre calculous

OpenStudy (sleepyjess):

I took precal in 10th grade, A line is perpendicular to another if it meets or crosses it at right angles (90°). Perpendicular means "at right angles". A line meeting another at a right angle, or 90° is said to be perpendicular to it. http://www.mathopenref.com/perpendicular.html

OpenStudy (ram231):

|dw:1449806960244:dw| these can be perpendicular lines, and they don't cross at 90 degrees.....

OpenStudy (sleepyjess):

Those are not perpendicular lines

OpenStudy (ram231):

im not going to fight. But being in a house full of smart mathletes that compete in competitions and win... I know what they are....

OpenStudy (anonymous):

what is the isosceles triangle theorem?

OpenStudy (sleepyjess):

Sorry about that jcr, would you like to continue with the problems?

OpenStudy (anonymous):

yes please

OpenStudy (sleepyjess):

This is what I found about it: Isosceles Triangle Theorems. The Base Angles Theorem. If two sides of a triangle are congruent, then the angles opposite those sides are congruent. Converse of the Base Angles Theorem. http://www.mathwarehouse.com/geometry/congruent_triangles/isosceles-triangle-theorems-proofs.php

OpenStudy (sleepyjess):

I've actually never heard of that...

OpenStudy (sleepyjess):

Are we doing #50 right now?

OpenStudy (anonymous):

yes, #50

OpenStudy (sleepyjess):

Okay, we're looking for 2 angles that are 90 degrees, on line BD

OpenStudy (anonymous):

angle 1 and angle 2

OpenStudy (sleepyjess):

Yes! So for the statement on #2, it will be <1 \(\cong\) <2

OpenStudy (anonymous):

Okay. for 3. would it be reflexive?

OpenStudy (sleepyjess):

Now we have to figure out something that will make triangle ABD isosceles...

OpenStudy (anonymous):

Sides AB and AD are congruent. Would that be part of it? because isosceles has two = sides

OpenStudy (sleepyjess):

I feel like the statement is going to be AB \(\cong\) AD, but I'm not sure of the reason

OpenStudy (anonymous):

Okay, so what about #5? Im not sure on that one

OpenStudy (sleepyjess):

I honestly am just going around in circles with this....

OpenStudy (anonymous):

|dw:1449808300747:dw| This is what I have for markings on the picture

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