I WILL GIVE MEDAL Given triangle ABC with A(-4, -2), B(4, 4), and C(18, -8), Write the equation of the line containing the altitude that passes through B in standard form.
please help
anyone
i think for this you'd have to use the distance formula
how would i set that up
still very confused
can you explain more?
So since the altitude is perpendicular to the opposing side, we have have to find the equation of AC.
how do i do that
im sorry im very tired
that's fine same here
let's see: \[m = \frac{ -8 - (-2) }{ 18 - (-4) } = \frac{ -6 }{ 22 } = \frac{ -3 }{ 11 }\] But since we're looking for the perpendicular slope, we find the inverse reciprocal: \[\frac{ -3 }{ 11 } \rightarrow \frac{ 11 }{ 3 }\] this is our slope for the altitude. \[y = f(4) = 4 = \frac{ 11 }{ 3 } (4) + b\] now, we just have to pass through point B (4,4). So to get it in standard form: \[y-4 = \frac{ 11 }{ 3 }(x-4)\] \[y - 4 = (\frac{ 11 }{ 3 })x - \frac{ 44 }{ 3 }\] \[(\frac{ -11 }{ 3 })x + y = 4 - \frac{ 44 }{ 3 }\] \[\frac{ -11 }{ 3 }x + y = \frac{ -32 }{ 3 }\] and there you have it. But please double check my work just in case.
thank you so much
You're welcome
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