Question

I've forgotten how to set this problem up:

Answer 1

If \[\int\limits_{1}^{3}f(w)dw=7\]
find the value of
\[\int\limits_{1}^{2}f(5-2x)dx\]

Answer 2

Substitute \[5-2x=w\]

Answer 3

by f(omega) it means a periodic function right?

Answer 4

uh.... I don't think so

Answer 5

nishant is right!

Answer 6

@Nishant_Garg that doesn't work

Answer 7

Would work if the limits were the same

Answer 8

that does! 5-2x=w then -2dx=dw you need to change the limits then

Answer 9

\[5-2x=w\]\[dx=-\frac{1}{2}dw\]
Limits become 3 to 1