Question

help PLEASE, I will medal
In parallelogram PQRS, PT=2x, TR=y+4, QT=x+2, and TS=y. Find the values of x and y.

Answer 1

@Cardinal_Carlo help please

Answer 2

i'll see what I can do, give me a few minutes

Answer 3

sure thing

Answer 4

Since this is a parallelogram, the opposing sides are parallel, and since the the crossing segments attach to opposing corners, we can safely say that each crossing segment bisects the other.

So:
\[PT = TR \rightarrow 2x = y + 4 \rightarrow 2x - 4 = y\]
AND
\[QT = TS \rightarrow x + 2 = y\]
Now that we have two defined equations from the same model, we can proceed by equating the two to get our variables x and y:
\[2x - 4 = x + 2\]
Solve for x:
\[x = 6\]
plug into either equation to get y. I'll choose the simplest one:
\[y = (6) + 2 = 8\]

and there you have it.
\[x = 6\]
AND
\[y = 8\]

Answer 5

Thanks so much!(:

Answer 6

You're welcome again :)