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Mathematics 10 Online
OpenStudy (lord2clash):

Can i get help with Area and Perimeters of Polygons?

OpenStudy (lord2clash):

OpenStudy (lord2clash):

@the_ocean_girl can you help with this?

Theoceangirl (the_ocean_girl):

Ouch sorry Clash. Not in that part of geometry yet!

OpenStudy (lord2clash):

okay cx thanks anyways cx

OpenStudy (anonymous):

So what work have you gotten done on it so far?

OpenStudy (lord2clash):

the area of the unshaded section is 320 and thats it...

OpenStudy (anonymous):

And do you have any clue how you'd find the shaded area?

OpenStudy (lord2clash):

not exactly i saw the formula (i think) somewhere but i cant find it now...

OpenStudy (anonymous):

Well to find the shaded area we would do \[\large \sf Area~of~hexagon~-~Area~of~unshaded~region~=~Area~of~shaded~area\] Since we have the area of the unshaded region, what we need to find now is the area of the hexagon. Do you know how to do that?

OpenStudy (lord2clash):

Honestly no. i didn't read the section on it.... but im willing to learn how cx

OpenStudy (anonymous):

Probably the easiest way is \[\large \sf Area= \frac{1}{2} \times perimeter \times apothem\] but you can only use this way if you have the apothem.

OpenStudy (lord2clash):

witch i do cx

OpenStudy (lord2clash):

apothem = 17.32

OpenStudy (lord2clash):

so 1/2(20*6)17.32

OpenStudy (anonymous):

Yup

OpenStudy (lord2clash):

1039.2?

OpenStudy (lord2clash):

so A?

OpenStudy (anonymous):

Yup. Now subtract the area of the unshaded region to get your answer.

OpenStudy (lord2clash):

710 B

OpenStudy (anonymous):

Correct

OpenStudy (lord2clash):

thanks cx

OpenStudy (anonymous):

No problem

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