Can i get help with Area and Perimeters of Polygons?
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OpenStudy (lord2clash):
OpenStudy (lord2clash):
@the_ocean_girl can you help with this?
Theoceangirl (the_ocean_girl):
Ouch sorry Clash. Not in that part of geometry yet!
OpenStudy (lord2clash):
okay cx
thanks anyways cx
OpenStudy (anonymous):
So what work have you gotten done on it so far?
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OpenStudy (lord2clash):
the area of the unshaded section is 320 and thats it...
OpenStudy (anonymous):
And do you have any clue how you'd find the shaded area?
OpenStudy (lord2clash):
not exactly i saw the formula (i think) somewhere but i cant find it now...
OpenStudy (anonymous):
Well to find the shaded area we would do \[\large \sf Area~of~hexagon~-~Area~of~unshaded~region~=~Area~of~shaded~area\] Since we have the area of the unshaded region, what we need to find now is the area of the hexagon. Do you know how to do that?
OpenStudy (lord2clash):
Honestly no. i didn't read the section on it....
but im willing to learn how cx
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OpenStudy (anonymous):
Probably the easiest way is \[\large \sf Area= \frac{1}{2} \times perimeter \times apothem\] but you can only use this way if you have the apothem.
OpenStudy (lord2clash):
witch i do cx
OpenStudy (lord2clash):
apothem = 17.32
OpenStudy (lord2clash):
so 1/2(20*6)17.32
OpenStudy (anonymous):
Yup
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OpenStudy (lord2clash):
1039.2?
OpenStudy (lord2clash):
so A?
OpenStudy (anonymous):
Yup. Now subtract the area of the unshaded region to get your answer.
OpenStudy (lord2clash):
710 B
OpenStudy (anonymous):
Correct
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