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OpenStudy (melissa_something):

What's the charge of Fe2S3 ?

OpenStudy (melissa_something):

\[Fe _{2}S _{3}\]

OpenStudy (jfraser):

\(Fe_2S_3\) \(has\) no net charge, the formula is \(neutral\)

OpenStudy (melissa_something):

Oh, but how do you know? I'm beating myself up trying to find the charge of Fe

OpenStudy (jfraser):

you're looking at 2 different things. The charge of a \(molecule\) is always neutral. the charges of the \(ions\) that make up the formula is what you're really asking for, right?

OpenStudy (melissa_something):

It just asks me what the charge of it is, then says +2, -2, +3, etc

OpenStudy (melissa_something):

I don't know :(

OpenStudy (jfraser):

because transition metals usually have more than one option for their charge, it's helpful to look at the ion they are \(paired \space to\) to find the opposite charge, since they must add up to zero.

OpenStudy (jfraser):

in this formula, the iron is paired with sulfur. what kind of ion does sulfur form?

OpenStudy (melissa_something):

I thought I had a clue but my brain just farted, would it be cation? Idk how to tell

OpenStudy (jfraser):

it's listed second in the formula, meaning the sulfur will have a negative charge. sulfur is also in the same family as \(oxygen\), so if you know the charge that oxygen forms, sulfur will be the same

OpenStudy (melissa_something):

The charge would be 6, right?

OpenStudy (melissa_something):

Does the element listed second in a formula always have a negative charge?

OpenStudy (jfraser):

6 is the number of valence electrons sulfur has, not its charge.

OpenStudy (jfraser):

yes, the non-metal in an ionic compound (which is always listed second) will always have a negative charge

OpenStudy (melissa_something):

Of course... then how do you tell?

OpenStudy (melissa_something):

Okay that helps

OpenStudy (jfraser):

do you know the much about valence electrons, or atomic orbitals & quantum numbers?

OpenStudy (melissa_something):

Yes, I always seem to forget the simple stuff

OpenStudy (jfraser):

ok, then what's the "magic" number of valence electrons to make an atom happy?

OpenStudy (melissa_something):

The nearest one to the noble gas, no?

OpenStudy (jfraser):

yes, and how many valence electrons do the noble gases have?

OpenStudy (melissa_something):

8

OpenStudy (jfraser):

good

OpenStudy (jfraser):

so a sulfur atom has 6 valence electrons, it "wants" 8 to look just like argon and be "happy"

OpenStudy (jfraser):

how many electrons does the sulfur have to pick up to look just like argon?

OpenStudy (melissa_something):

Yeah :D

OpenStudy (melissa_something):

2!

OpenStudy (jfraser):

great, so picking up 2 valence electrons turns the sulfur \(atom\), \(S\), into the sulfide \(ion\), \(S^{-2}\)

OpenStudy (jfraser):

the charge of a sulfide ion is -2

OpenStudy (jfraser):

in this formula, there are \(three\) sulfide ions, right?

OpenStudy (melissa_something):

Yes there is

OpenStudy (melissa_something):

We multiply?

OpenStudy (jfraser):

since each sulfide ion has a charge of -2, and there are 3 of them, what's the \(total\) negative charge?

OpenStudy (melissa_something):

-6!!!!

OpenStudy (jfraser):

exactly

OpenStudy (melissa_something):

Woah

OpenStudy (jfraser):

since the \(total\) charge of the irons \(MUST\) balance the charges from the sulfides, what must the \(total\) positive charge be?

OpenStudy (melissa_something):

Positive 6

OpenStudy (melissa_something):

So we multiply by 3 right?

OpenStudy (jfraser):

so what we've got is basically this: \(Fe_2S_3\) \(2*(+?) + 3*(-2) = 0\)

OpenStudy (melissa_something):

Oh so yeah we have to multiply by three

OpenStudy (jfraser):

there's +6 of total positive charge. that positive charge is going to be split evenly between the irons. there are 2 iron ions. What is the charge on \(each\) iron ion going to be?

OpenStudy (melissa_something):

3?

OpenStudy (jfraser):

it is a +3

OpenStudy (melissa_something):

Yes!

OpenStudy (jfraser):

the same basic rules apply to all ionic compounds. the total charge must be zero, so there must be enough positive and negative pieces to balance that charge

OpenStudy (melissa_something):

I see, but I think we're talking about two different things, the answer should be +3 :C

OpenStudy (jfraser):

we're actually talking about the exact same thing. You have to use the rules of ionic formulas to figure out what the charges of the partners are

OpenStudy (melissa_something):

Okay, I'll research it!!! It made me confused bc of the +3

OpenStudy (jfraser):

if the question is "what's the charge of the \(iron\) in the \(Fe_2S_3\)", then the answer is certainly a +3

OpenStudy (melissa_something):

Oh... because Fe is the metal ion. I feel so bad. Duh!

OpenStudy (whpalmer4):

And you'll sometimes see that written as iron(III) sulfide to indicate that the iron is in the +3 state. That compound is also known as pyrite or iron pyrite or fool's gold, the last because it makes shiny crystals that look a bit like gold.

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