How long is a pendulum with a period of 1.0 s on a planet with half the gravity of the earth?

Question

daniellelovee · Answer

@satellite73

directrix · Answer

@KeplJoey offers the following:

The formula relating period, length and gravity is given by 

 T = 2π√(L/g). 

 We want to find the length, so we need to solve for L. Dividing through by 2π, then squaring both sides, then multiplying through by g, results in 

 L = gT²/4π². 

We're given that T = 1.0 s, and the gravity has half that on earth, or 
 g = 4.9 m/s². 

Putting in this info gives 

 L = 0.124 m. 

@Daniellelovee