Question

Perform the indicated operations.

Answer 1

anyone?

Answer 2

@pooja195

Answer 3

First get common denominator.

Answer 4

20?

Answer 5

Yeap, thats a great way to start.

Answer 6

ok now what?

Answer 7

Combine it into a single fraction.

Answer 8

a+2+a-1+a-3?

Answer 9

You got: \[\frac{a+2}{4b}-\frac{a-1}{10b}+\frac{a-3}{5b}\]\[=\frac{5(a+2)}{20b}-\frac{2(a-1)}{20b}+\frac{4(a-3)}{20b}\]

Answer 10

ok

Answer 11

Now we have the same denominator. Now we want to get them into a single fraction. So we get:
\[\frac{5(a+2)-2(a-1)+4(a-3)}{20b}\]

Answer 12

Now the next step would be to simplify the nominator.

Answer 13

5a+10-2A+2+4A-12

Answer 14

Correct

Answer 15

Try so simplify it further

Answer 16

7A

Answer 17

Yes, so the final answer is \[\frac{7a}{20b}\]

Answer 18

7A/20B?

Answer 19

Yea! good job :)

Answer 20

THANKS I HAVE ONE MORE QUESTION

Answer 21

sure

Answer 22

Solve the inequality.

Answer 23

these are ones i don't understand

Answer 24

Okay, lets get common denominator first.

Answer 25

6

Answer 26

Yeap, so we get\[\frac{2x}{6}+\frac{3(1-x)}{6}\ge1\]

Answer 27

Lets put it into a single fraction.

Answer 28

\[\frac{2x+3(1-x)}{6}\ge1\]

Answer 29

Try and simplify the nominator