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Mathematics 16 Online
OpenStudy (seb.cal):

CORRECT ANSWER = MEDAL + FAN + TESTIMONIAL Question is attached to my first comment.

OpenStudy (seb.cal):

OpenStudy (seb.cal):

@JesseReyna

OpenStudy (jessereyna):

Hey

OpenStudy (jessereyna):

Do you know how to factor?

OpenStudy (seb.cal):

Yeah, but I SUCK @ it... I always get it wrong, seriously.

OpenStudy (whovianchick):

4z^2-16z+5 ------------ the two z^2's cancel out 2z^2+z-15 4-16z+5 -------- the two z's cancel out 2+z-15 4-16+5 ------- combine like terms 2-15 -7 7 --- = ---- -13 13

OpenStudy (whovianchick):

Do you have answer choices?

OpenStudy (seb.cal):

Yeah, I'll post them.

OpenStudy (insertnamehere352):

4z^2-16z+5 ------------ the two z^2's cancel out 2z^2+z-15 4-16z+5 -------- the two z's cancel out 2+z-15 4-16+5 ------- combine like terms 2-15 -7 7 --- = ---- -13 13

OpenStudy (seb.cal):

OpenStudy (jessereyna):

You can't cancel out like that if there are adding and subtracting terms

OpenStudy (jessereyna):

Need to factor

OpenStudy (jessereyna):

Okay ill do it in word and then post it brb

OpenStudy (whovianchick):

No, you don't need to factor.

OpenStudy (astrophysics):

@whovianchick huh that makes no sense

OpenStudy (whovianchick):

x^2 x x^2+x ---- +---- is the same thing as -------- x^2 x x^2+x

OpenStudy (astrophysics):

No it's not

OpenStudy (astrophysics):

Factor @seb.cal

OpenStudy (whovianchick):

oh

whitemonsterbunny17 (whitemonsterbunny17):

Just a friendly reminder that direct answers are against the Anti-Cheating Policy. Even if you explain the answer afterward. Have a wonderful day, everyone!

OpenStudy (whovianchick):

i just thought about that

OpenStudy (seb.cal):

I figured I had to b/c the math that she did didn't match up with the answers.

OpenStudy (whovianchick):

IGNORE ME I GOT IT WRONG SUPER SORRY

OpenStudy (astrophysics):

|dw:1449865202144:dw|

OpenStudy (seb.cal):

@Whitemonsterbunny17 This is from a pretest.

OpenStudy (astrophysics):

Ok first lets factor the denominator, do you know how to do that?

OpenStudy (astrophysics):

Doesn't matter if it's a pretest, why would you want answers to just a pretest then...pretests are used to help you learn

OpenStudy (seb.cal):

By multiplying the 1st and 3rd terms, right? Then seeing if the factors match up to equal 1?

OpenStudy (astrophysics):

Mhm, well there's a 2 as a coefficient so it's a bit trickier, we want the product of 2 and -15 then figure out the factors -30

OpenStudy (astrophysics):

\[2z^2+z-15 \implies 3(2z-5)+z(2z-5)\]

OpenStudy (seb.cal):

Factors of -30: -30 and 1 5 and -6 (or reversed).

OpenStudy (seb.cal):

Oh, I see what you did there.. Okay, then what I do with that?

OpenStudy (astrophysics):

Now you must factor the numerator

OpenStudy (astrophysics):

Since we have \[\frac{ 4z^2-16z++15 }{ (3-z)(2z-5) }\]

OpenStudy (astrophysics):

that should be 3+z

OpenStudy (astrophysics):

So find the product of 4 and 15, then ask which two numbers add up to -16 and multiply to give that product

OpenStudy (seb.cal):

4 times 15 = 60. Factors of 60 = 60 and 1 6 and 10 5 and 12 3 and 20 4 and 15

OpenStudy (seb.cal):

but, I didn't do the negative side... So the answer would be -6 and -10?

OpenStudy (astrophysics):

Right so our product is 60, now note the middle number sorry I wasn't clear about it earlier, we want two numbers to add up to -16 and multiply to give 60

OpenStudy (astrophysics):

Yes exactly!

OpenStudy (seb.cal):

Woohoo! Yes!! alright, tehn since we have the denominator down... How exactly would I "plug in" -6 and -10 into the numerator?

OpenStudy (astrophysics):

So this is how we do it |dw:1449865798827:dw| see we replaced the -16z

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