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Chemistry 14 Online
OpenStudy (anonymous):

Combustion analysis of an unknown compound provides the following data: 98.28 grams carbon (C), 16.21 grams hydrogen (H), and 65.52 grams oxygen (O). What is the percent composition of carbon in this compound? 6.06% C 54.6% C 33.3% C 36.4% C

OpenStudy (anonymous):

@sammyalabamy can you help me plz?

OpenStudy (anonymous):

@Astrophysics Can you help me plz?

OpenStudy (astrophysics):

Ooh I remember doing this back in the day..let me see now

OpenStudy (astrophysics):

Ok so we have C = 98.28g, H = 16.21 g, and O = 65.2 g right

OpenStudy (anonymous):

Yes @Astrophysics

OpenStudy (astrophysics):

Ok so what is the total number of grams?

OpenStudy (anonymous):

Do i suppose to add them together? @Astrophysics

OpenStudy (astrophysics):

Yes, add it all together what do you get?

OpenStudy (anonymous):

179.69 @Astrophysics

OpenStudy (astrophysics):

Good, now simply take the number of grams from carbon and divide it by the total amount which will give you a ratio of the amount of carbon in the compound

OpenStudy (astrophysics):

Then multiply by 100 for the percent :) make sense?

OpenStudy (astrophysics):

\[\frac{ Carbon }{ Total } \times 100\]

OpenStudy (anonymous):

98.28g divide by 179.69g= 0.546 ....Right?

OpenStudy (astrophysics):

Good! Now multiply by 100 for the percent :)

OpenStudy (anonymous):

0.546 x 100=54.6

OpenStudy (astrophysics):

:)

OpenStudy (anonymous):

yayyy thank you @Astrophysics

OpenStudy (astrophysics):

Yw

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