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Chemistry 7 Online
OpenStudy (anonymous):

Methane, CH4, burns in oxygen gas to form water and carbon dioxide. What is the correct balanced chemical equation for this reaction? A. CH4 + O → H2O + CO2 B. CH4 + 4O → 2H2O + CO2 C. CH4 + O2 → H2O + CO2 D. CH4 + 2O2 → 2H2O + CO2

OpenStudy (anonymous):

@KendrickLamar2014 do u know how to do this?

OpenStudy (anonymous):

@Astrophysics

OpenStudy (kendricklamar2014):

Im not good at Chemistry :P Sorry

OpenStudy (anonymous):

me neither! its okee ^_^ thanks anyway:D

OpenStudy (astrophysics):

Burns oxygen, note that oxygen is a diatomic element which means?

OpenStudy (anonymous):

doesn't form peroxide...

OpenStudy (anonymous):

mkay....still a little confused.....

OpenStudy (sweetburger):

combustion reactions will always have co2 and h2o as products

OpenStudy (sweetburger):

therefor you just have to balance the equation and pick the correct answer

OpenStudy (astrophysics):

It gives you the reaction you simply have to remember the basics, oxygen and carbon = diatomic elements meaning there's always 2. Then balance the equation

OpenStudy (anonymous):

oooooh! okay! :D

OpenStudy (astrophysics):

So diatomic means \[O_2, N_2, F_2\] sorry I said carbon was diatomic it isn't haha

OpenStudy (astrophysics):

There's 7 elements that fall into this category

OpenStudy (astrophysics):

\[CH_4 + O_2 ->\] what's next

OpenStudy (astrophysics):

(Note we will still have to balance it after)

OpenStudy (anonymous):

okay now can you help me with the balancing part? im totally not good at all of this

OpenStudy (anonymous):

idk whats next >.< ugh

OpenStudy (astrophysics):

Read the question, what are the products

OpenStudy (astrophysics):

Just set up the unbalanced equation right now and we'll balance it after

OpenStudy (anonymous):

tahts the thing i need help understanding...setting up the equations...>.< im homeschooled and dont have a teacher

OpenStudy (astrophysics):

Methane, CH4, burns in oxygen gas to form water and carbon dioxide. \[Ch_4 + O_2 -> H_2O+CO_2\] reading what you have should be able to set it up as above

OpenStudy (astrophysics):

\[CH_4 + O_2 -> H_2O+CO_2\]

OpenStudy (astrophysics):

Now you have to balance the amount of carbon, oxygen, hydrogen etc

OpenStudy (astrophysics):

Notice there are 4 hydrogens on the left, and 2 on right so you can multiply the on right to balance it with the left, see if you can figure this out

OpenStudy (anonymous):

ITS D!!

OpenStudy (anonymous):

yups 'D' is the answer

OpenStudy (anonymous):

awesome thanks everyone! :D

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