Question

Who understands what log is in math? I have never learned it and it is on my ACT Prep assignment

Answer 1

@Whitemonsterbunny17 @Elsa213 @tatumlee

Answer 2

The logarithm?
It's an operation which is the inverse of the exponential operation.

Example:\[\large\rm 2^3=8\]This exponential operation is a base of 2 raised to the 3rd power.
And the output is 8.

\[\large\rm \log_28=3\]This log operation is a base of 2 and it takes the number 8 and spit outs a 3.

It's like it's giving us the exponent as a result.
The log is good for dealing with really really large scale numbers.
It's how they measure earthquakes and other interesting stuff :)

Answer 3

Log has some weird properties:\[\large\rm \log(ab)=\log(a)+\log(b)\]\[\large\rm \log\left(\frac{a}{b}\right)=\log(a)-\log(b)\]\[\large\rm \log(a^b)=b\cdot \log(a)\]

Answer 4

then what does \[\log_{10} A/B\]

Answer 5

If log is showing up on your ACT,
they probably want you to apply these three rules some how.

Answer 6

I dont understand

Answer 7

Is that the entire question?
Do they want you to "expand" it?

Answer 8

thats the entire question with options that come with it.

Answer 9

can you list at least one of the options so I have an idea of what they want? c:

Answer 10

these are the options

Answer 11

Well did you notice the 3 rules I listed for log a moment ago? :)
It looks like that middle one \(\large\rm \log\left(\frac{a}{b}\right)=\log(a)-\log(b)\) is useful for our problem here.

Answer 12

Replace a with A,
and b with B,
and give the log a base of 10,\[\large\rm \log_{10}\left(\frac{A}{B}\right)=\log_{10}(A)-\log_{10}(B)\]

Answer 13

If you haven't done any work with logs,
then yes, these are going to be confusing.

You just need to try and follow how these three rules work :)

Answer 14

I havent learned any of the cos, sig, or the logs terms. Im not that smart Dx

Answer 15

wait. I don't see an option of what you gave me for the problem.... Dx

Answer 16

ACT is a good test :)
Try to do well on it.

You don't want to rely on SAT, that one is a real piece of garbage.

You can at least take educated guesses on some of these ^^ hehe

Answer 17

You don't?
It's the option below the one you highlighted.
Keep in mind that \(\large\rm \log_{10}(A)-\log_{10}(B)\quad=\log_{10}A-\log_{10}B\)
The brackets don't matter.

Answer 18

oh okay. thats what was confusing. thanks! Be my tutor hahaha (:

Answer 19

XD

Answer 20

what? Ill need it! hahahaa