Question

What is the discontinuity and zero of the function f(x) = 2x^2+5x-12
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x+4

Answer 1

Answers:
Discontinuity at (−4, −11), zero at ( three halves , 0)
Discontinuity at (−4, −11), zero at ( negative three halves , 0)
Discontinuity at (4, 5), zero at ( three halves , 0)
Discontinuity at (4, 5), zero at ( negative three halves , 0

Answer 2

Please help, @Directrix

Answer 3

Factor this: 2x^2+5x-12

I am thinking that the denominator (x +4) will be a factor. If it is, we need to see the other factor.

Answer 4

(2x-3)(x+4)

Answer 5

(2x-3)(x+4)
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(x + 4)

Before dividing out the (x + 4) factors, take note that a point of discontinuity will occur when x = -4 because the denominator is 0 when x = -4.

Answer 6

Looking at my answers, I've got two that have -4, 11 as the discontinuity.

Answer 7

f(x) = (2x-3) where x is not -4

@DeadMovies

Find f(-4) to get the y coordinate of the point of discontinuity

f(-4) = (2*(-4) - 3)

Multiply 2 times -4 and then subtract 3 from the product.

Answer 8

Okay, so my choices with those two numbers(-4, -11) as discontinuities are A, and B.

Now we work on the zeros?
@Directrix @mathmale

Answer 9

The zero is the x-intercept.

f(x) = (2x-3)

(2x-3)= 0

x = ?

Answer 10

@DeadMovies