WILL FAN AND MEDAL : Company A charges $50 dollars per day. Company B charges only $18 dollars per day and $0.10 per mile driven. In one day, how many miles would a renter have to drive for he car from Car A be better from Car B? Express answer as a whole number.
So, we have that A = $50 no matter what B starts at $18, but .10 for each mile What would we do to find out how much, let's say... 10 miles for example cost?
Sorry i messed up its actually 38 dollars for car b. An .01*10=1
Alright, no problem.. and not exactly. The .01 stands for one cent, not one dime
but it says 10 cents per mile?
Whoa, did it glitch?
But the equation you have is basically saying 10 pennies = 1 dollar
Where you want it to say 10 dimes = 1 dollar because it's a dime for each mile and we needed 10 miles in our example
ok
Because of that we would get .10*10 Now, the 10 miles was an example, but we are trying to find the number of miles to equal $50.10, right? Since that would be the point where Car A would be the better choice, so the 10 would be an X, making it .10(x)
That would be part of an equation we need. If I told you that Car A = Initial price of Car B + .10(x), could you fill in the numbers?
50=38+.10(x) what would x equal? i say about 200
Correct equation! The answer is alittle less though To find it, we have to get the 38 on the other side first
subtract 38 from 50 =12?
Correct! So we have 12=.10x Two more steps: 1.) How would you get the .10 away from the x?
12/.1 = x
Exactly! That will get you an x value But remember, we made the equation equal, so after finding x, you simply add a mile to get your answer
can you walk me through the rest?
Sure Can you divide 12/.1?
yes it gives you 120
Correct, so now we have Car A = Car B But we wanted Car B to be greater than Car A, so we add one mile simply to get..?
you lost me >.< sorry
So we had that Car A = $50 right and Car B = $38 + .10 for each mile We wanted Car A to equal Car B We found out through formulas that in order to get Car A as much as Car B ($50), we would need to drive 120 miles So we have that Car A = Car B, or $50 = $50 But the question wanted to know when Car A would be better than Car B, which means when would it be cheaper, since cheaper is better So in order to get Car A better, we would need to add another 10 cents, to make Car A = $50 and Car B = $50.10 ^ Better ^ Worse In order to get that extra 10 cents, how many extra miles would we need to add?
Ah, no need for saying sorry. I'm here to help =]
1?
Right So we would get the answer we got, 120, and add one to it to get our final answer
121?
Exactly, thats the answer!
thank you!!!!!!!!!
Anytime!
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