Okay, so I was looking at my College Algebra book for next semester, and I'm confused on at least one thing so far. Graphing a sequence, can anyone help?

Question

sleepyjess · Answer

The example in the book is:
Write down the first six terms of the following sequence and graph it.

$a_n = \dfrac{n-1}n$

How do I know what the x and y values are?

sleepyjess · Answer

So for a = 1

$a_1 = \dfrac{1-1}1 = 0$
Would x be 1 and y be 0? Making the coordinate (1, 0)?

sleepyjess · Answer

Then $a_2 = \dfrac{2-1}2 = \dfrac12$
x = 2 and y = 1/2? Making the coordinate (2, 1\2)?

sleepyjess · Answer

Do I have the right idea or nah? :)

shadowlegendx · Answer

You read your books before school starts? Jess you tryhard

sleepyjess · Answer

lol, I like math and I haven't taken it yet this year, so I was refreshing :P

mathmale · Answer

$$a _{n}=\frac{ x-1 }{ n }$$

mathmale · Answer

There are no x or y here, although you can graph this sequence.
Just let n begin with the value 1 and increase it:  1, 2, 3, 4, .....

The first 2 terms are 

$$\frac{ 2-1 }{ 2 },\frac{ 3-1 }{ 3 }$$

mathmale · Answer

These terms can, of course, be simplified.

sleepyjess · Answer

What would I use for coordinates to graph it?

sleepyjess · Answer

Wouldn't the first term be $\dfrac01$?

jim_thompson5910 · Answer

@sleepyjess you are correct

each point generated by the sequence is of the form (n, f(n))

f(n) is the function rule for the sequence, in this case, f(n) = (n-1)/n

jim_thompson5910 · Answer

n is a natural number (it is a positive whole number)

sleepyjess · Answer

Thanks both of you :)