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Help me prove this please???
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\[\frac{ 1 - \sin \theta }{ \sec \theta } = \frac{ \cos^3 \theta }{ 1 + \sin \theta }\]
Take left hand side and multiply by a special kind of 1 : \[\dfrac{1+\sin\theta}{1+\sin\theta}\]
I already started the problem, and I'm wondering if I can simplify the left hand side by changing the sec to 1/cos, which then, you can multiply the numerator by cos and the denominator is just 1.
Did you take time to read my reply thoroguhly ?
Yes?, but I was wondering if I can simplify the sec theta first...
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you could do that
And then, I should multiply by the special kind of 1 right?
Yes, give it a try
alright thanks.
Yup, I proved it!
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