When using the equation y^2 = 4ax to find the equation of a parabola, how do I know what "a" is?
Example, Question: Find an equation of the parabola with vertex at (0, 0) and focus at (3, 0). Solution: The distance form the vertex (0, 0) to the focus (3, 0) is a = 3. Based on equation 2, the equation of this parabola is \(y^2 = 4ax\) \(y^2 = 12x\)
Where do they get the 3 from?
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This was a huge struggle point last year for me >_<
So the x coordinate of the focus is "a"?
Yup :)
So, Question: Find an equation of the parabola with vertex at (1, 2) and focus at (4, 8). Would "a" still be 4?
And depending on the equation, the graph will look differently. And from the equation you can tell where the focus would be by knowing what 'a' is :)
Idek if that would be a possible vertex and focus, just an example
For that kind of question, you have to use another formula: (x-h)^2 = 4p(y-k)
How do I know what h, k and p are?
Vertex is (h, k) right?
As always, (h,k) is the vertex
And, for p "The absolute value of p is the distance between the vertex and the focus and the distance between the vertex and the directrix."
My book says 4a, is there any difference between p and a?
I guess not lol
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