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Mathematics 19 Online
OpenStudy (anonymous):

Help

OpenStudy (braydonlevi99):

What is your question?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

help

ganeshie8 (ganeshie8):

\(4+5x-6x^2 = (-43/4)H_1+5H_2 +(19/4)H_3\)

OpenStudy (anonymous):

ok so we equate them and thats it?

ganeshie8 (ganeshie8):

that is the linear combination

ganeshie8 (ganeshie8):

read the question again

ganeshie8 (ganeshie8):

you want to check if there exist numbers \(a,b,c\) such that : \(4+5x-6x^2 = a*H_1+b*H_2 +c*H_3\)

ganeshie8 (ganeshie8):

plugin the given polynomials for \(H_1, H_2, H_3\) above and get : \(4+5x-6x^2 = a*x^2+b*(x-3) +c*(x^2+4)\)

ganeshie8 (ganeshie8):

compare coefficients both sides

ganeshie8 (ganeshie8):

maybe start by comparing \(x\) coefficient both sides

ganeshie8 (ganeshie8):

Look at below equation \(4+5x-6x^2 = a*x^2+b*(x-3) +c*(x^2+4)\)

ganeshie8 (ganeshie8):

whats the coefficient of x on left hand side ?

ganeshie8 (ganeshie8):

whats the coefficient of x on right hand side ?

ganeshie8 (ganeshie8):

Yes, the coefficients must be equal both sides, therefore \(b=5\)

ganeshie8 (ganeshie8):

next compare constant terms both sides and try finding another variable

ganeshie8 (ganeshie8):

whats the constant term on left hand side ?

OpenStudy (anonymous):

4

ganeshie8 (ganeshie8):

what about right hand side ?

OpenStudy (anonymous):

c4

ganeshie8 (ganeshie8):

nope, try again

OpenStudy (anonymous):

-3b+c4?

ganeshie8 (ganeshie8):

Yes, the constant terms must be equal on both sides : 4 = -3b + 4c

ganeshie8 (ganeshie8):

plugin the value of \(b\) and solve \(c\)

OpenStudy (anonymous):

4=-3(5)+4c , 19=4c , 19/4=c

ganeshie8 (ganeshie8):

Yes, compare x^2 coefficients both sides and try finding the value of \(a\) too

ganeshie8 (ganeshie8):

i got a = -43/4

ganeshie8 (ganeshie8):

please double check ur work

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