Mathematics
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OpenStudy (anonymous):
Help
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OpenStudy (braydonlevi99):
What is your question?
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
help
ganeshie8 (ganeshie8):
\(4+5x-6x^2 = (-43/4)H_1+5H_2 +(19/4)H_3\)
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OpenStudy (anonymous):
ok so we equate them and thats it?
ganeshie8 (ganeshie8):
that is the linear combination
ganeshie8 (ganeshie8):
read the question again
ganeshie8 (ganeshie8):
you want to check if there exist numbers \(a,b,c\) such that :
\(4+5x-6x^2 = a*H_1+b*H_2 +c*H_3\)
ganeshie8 (ganeshie8):
plugin the given polynomials for \(H_1, H_2, H_3\) above and get :
\(4+5x-6x^2 = a*x^2+b*(x-3) +c*(x^2+4)\)
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ganeshie8 (ganeshie8):
compare coefficients both sides
ganeshie8 (ganeshie8):
maybe start by comparing \(x\) coefficient both sides
ganeshie8 (ganeshie8):
Look at below equation
\(4+5x-6x^2 = a*x^2+b*(x-3) +c*(x^2+4)\)
ganeshie8 (ganeshie8):
whats the coefficient of x on left hand side ?
ganeshie8 (ganeshie8):
whats the coefficient of x on right hand side ?
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ganeshie8 (ganeshie8):
Yes, the coefficients must be equal both sides, therefore \(b=5\)
ganeshie8 (ganeshie8):
next compare constant terms both sides and try finding another variable
ganeshie8 (ganeshie8):
whats the constant term on left hand side ?
OpenStudy (anonymous):
4
ganeshie8 (ganeshie8):
what about right hand side ?
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OpenStudy (anonymous):
c4
ganeshie8 (ganeshie8):
nope, try again
OpenStudy (anonymous):
-3b+c4?
ganeshie8 (ganeshie8):
Yes, the constant terms must be equal on both sides :
4 = -3b + 4c
ganeshie8 (ganeshie8):
plugin the value of \(b\) and solve \(c\)
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OpenStudy (anonymous):
4=-3(5)+4c , 19=4c , 19/4=c
ganeshie8 (ganeshie8):
Yes, compare x^2 coefficients both sides and try finding the value of \(a\) too
ganeshie8 (ganeshie8):
i got a = -43/4
ganeshie8 (ganeshie8):
please double check ur work