Compute the value of the discriminant and give the number of real solutions of the quadratic equation -7x^2-8x-3=0
\(ax^2 + bx + c = 0\) \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) \(b^2 - 4ac\) is the discriminant. If the discriminant is positive, there are 2 different real roots. If the discriminant equals zero, the is one real root with multiplicity 2. If the discriminant is negative, there are two complex roots.
mathstudent55 has it right. There's a little more to the discriminant, however. If the discriminant is positive, there are two real roots: that are rational numbers if the discriminant is a perfect square; that are irrational numbers if the discriminant isn't a perfect square. I created a video that explains the quadratic formula and the discriminant. It may provide additional assistance to you: https://www.youtube.com/watch?v=W0zIsspXh4g
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