Question

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Answer 1

@MARC_

Answer 2

Example

Answer 3

Now the question is asking which value of x can make the denominator become zero

Answer 4

-1/4 is not the answer

Answer 5

i tried them and 1/4 made it 0

Answer 6

*1/4

Answer 7

well try substitute option A into \[\frac{ 8x-2 }{ 5x+1 }\]

Answer 8

\[=\frac{ 8(-\frac{ 1 }{ 5 })-2 }{ 5(-\frac{ 1 }{ 5 })+1 }\]

Answer 9

\[=\frac{ -\frac{ 8 }{ 5 }-2 }{ -1+1 }\]

Answer 10

\[=\frac{ -2\frac{ 8 }{ 5 } }{ 0 }\]

Answer 11

\[=\frac{ \color{red}{-2\frac{ 8 }{ 5 }} }{ 0 }\]convert the mixed number into proper fraction

Answer 12

*improper fraction

Answer 13

\[=\frac{ -\frac{ 18 }{ 5 } }{ 0 }\]

Answer 14

\[=-\frac{ 18 }{ 5 }\div \frac{ 0 }{ 1 }\]

Answer 15

\[=-\frac{ 18 }{5 }\times \frac{ 1 }{ 0 }\]

Answer 16

\[=-\frac{ 18\times1 }{ 5\times0 }\]

Answer 17

\[=-\frac{ ? }{ ? }\]solve it @Diana.xL

Answer 18

i think its undefined

Answer 19

option C is wrong bocz the numerator is zero not the denominator\[=\frac{ 8(\frac{ 1 }{ 4 })-2 }{ 5(\frac{ 1 }{ 4 })+1 }\]\[=\frac{ 2-2 }{ \frac{ 5 }{ 4 }+1 }\]\[=\frac{ 0 }{ 9 }\]

Answer 20

yes it's undefined and we know option A cause the denominator of the following expression to be zero..

Answer 21

For second question is correct...\[\frac{ x-3 }{ 2x^2+4x }\]\[2x^2+4x=0\]\[2x(x+2)=0\]\[2x=0,x+2=0\]\[Therefore,x \neq0~and~x \neq-2\]

Answer 22

is the last question correct?

Answer 23

yes \[12x^{20}+27x^5\]\[3x^5(4x^{15}+9)\]

Answer 24

thnx

Answer 25

yw