Help?
Question?
Question 4: Two equations are shown: • Equation 1: 3/4 (x−12)=12 •Equation 2: 3/4 y−12=12 Solve each equation. Then, enter a number in each box to make this statement true.
Ok, let's solve the first equation. Do you know what the first step would be?
Subtract 12-12?
No. Why would you think that?
That's what we learned in the lesson. Would I add 12 +12?
Well the first equation looks like this right? \[\large \sf \frac{3}{4}(x-12)=12\]
Yes
Then your first step is to distribute the \(\large \sf \frac{3}{4}\) onto the x and the -12.
How do I do that?
The distributive property. \[\large \sf a(x+y)=ax+ay\]
so it would be 3/4*x + 3/4*12
?
@linksonic1 I'm back to help
Okay thanks :)
So yes, your previous statement looks correct. So what would you get with that multiplication?
for 3/4*12 you get 9
Correct, and what about 3/4*x?
I don't know. How would I solve it without knowing what x is?
It was a bit of a trick question. All you would get is \(\large \sf \frac{3}{4}x\)
oooohh . Okay that's what I thought
haha, so it would now look like this \[\large \sf \frac{3}{4}x-9=12\] Now what would the next step be?
Now do I subtract the 12 and the 9 to get 3?
Well we want to get the 9 to the other side. So we will do the opposite of what it is now. Since the 9 is negative now, that means we will ADD 9 on both sides.
Okay so I will have a 18 where the 9 was and a 21 where the 12 was.
Almost. What is 9+(-9)?
0
Correct. So what you would get is a 0 where the 9 was and a 21 where the 12 was. \[\large \sf \frac{3}{4}x=21\]
So now I do 21 divided by 3/4?
In effect, yes. But when you want to divide a fraction, what you really do is multiply by it's reciprocal.
So 4/3*21
yep.
x = 28?
Correct :)
Yay thank you and would the answer be the same without the parenthesis?
No, because then you wouldn't distribute.
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