Question

An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirror.

The height of the image produced by the mirror, to the nearest tenth, is

Answer 1

Try using the Mirror Equation,\[M=\frac{ h_{i} }{ h_{o} }=-\frac{ d_{i}}{ d_{o} }\] Where, object distance (do), the image distance (di), image height (hi) and object height (ho)