x*e^sqrtx dx?
\(\large\color{#000000 }{ \displaystyle \int xe^\sqrt{x}dx }\) \(\large\color{#a11111 }{ \displaystyle u=\sqrt{x} }\) therefore, \(\large\color{#a11111 }{ \displaystyle x=u^2 }\) \(\large\color{#a11111 }{ \displaystyle du=\frac{1}{2\sqrt{x}}dx\quad \Longrightarrow \quad 2\sqrt{x}~du=dx\quad \Longrightarrow \quad 2u~du=dx}\) \(\large\color{#000000 }{ \displaystyle \int 2u^3e^udu }\)
From here you can do integration by parts 3 times to get rid of \(u^3\) in front of \(e^u\), and then don't forget to substitute back \(u=\sqrt{x}\) accordingly.
Alternatively, you can use the following series (if you have learned series techniques of integration) \(\large\color{#000000}{ \displaystyle e^u=\sum_{ n=0 }^{ \infty } ~ \frac{ u^n }{n!}}\)
Ohh, thank u
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