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Help needed with finding the slope intercept of a line. I don't understand why/how. (0,-2) m=3 y+2=3(x-0)
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y-y1=m(x-x1)---- this is the formula used to find a line where y1=-2 and x1=0
now can specify what you dont understand
yes I get the whole plug in numbers
solve for y now
Slope intercept is a form of the line in which you need the slope and the y-intercept. y=mx+b m=slope b=y-intercept The y-intercept occurs ant the point where 'x'=0 You are therefore given the y-intercept through (0,-2), and they plainly told you 'm' Just plug these into y=mx+b
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y+2=3x y=3x-2 then what?
That's it.
yeh thats is it
ok thanks
y=mx+b y=3x+b b is negative 2, so y=3x-2
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