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Express the integrand as a sum of partial fractions and evaluate the integral. Integral from 0 to 1 of (x^3)/ (x^2+8x+16) dx
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\[\int\limits_{0}^{1} \frac{ x^{3} }{ x ^{2}+8x+16}dx\] I've gotten as far as : \[\int\limits_{0}^{1} x+1+\frac{ 256 }{ (x+4)^{2} } +\frac{ 51 }{ (x+4)} dx\]
I think that is incorrect...
Ok, then how do I figure out A and B if the denominator is a perfect square?
before I do division, this is how you do it one fraction is (x+4) and the other is (x+4)^2
(I am talking denominators)
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