FREE MEDAL !!!!! She says that 2 is a zero of g(x) because long division with (x + 2) results in a remainder of 0. is that correct ?
What's g(x)? We would need to know that equation
Three party-goers are in the corner of the ballroom having an intense argument. You walk over to settle the debate. They are discussing a function g(x). You take out your notepad and jot down their statements.
Professor McCoy: She says that 2 is a zero of g(x) because long division with (x + 2) results in a remainder of 0.
there is no equation
She's wrong because assuming this is a polynomial the zero is -2
If a is a zero of f(x) then (x - a) will be a factor.
- and long division would give a zero reminder.
* remainder
s=i will be back in a sec I am working it out
In order to know the answer quickly, you can use examples to help you understand. The simplest polynomial with 2 being a zero is definitely x−2.
Prof McCoy: x−2x+2 definitely doesn't have a remainder of 0
she is wrong because in order that 2 be a zero of g(x), it is (x-2) which must be a factor of g(x), not (x+2). (FACTOR THEOREM) Ms. G is correct because if 2 is a zero of g(x), g(2) will be 0. (REMAINDER THEOREM) Mr. R is also correct because if (x-2) is a factor of g(x), g(x) will have 2 as a zero. (FACTOR THEOREM)
thanks welshfella and princess
Hint: for your question - look at the sign .
welcome :)
:)
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