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Solve the differential equation dq/dz = 2 + sin(z) with initial condition q(π) = 2π
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Dibs
you got it!
\[dq = 2+\sin(z) dz \implies \int\limits dq = \int\limits (2+\sin(z)) dz\]
separable*
Integrate it now
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alright so i got the portion with 2z-cos(z)
However im missing something
\[q = 2z-cosz+C\]
Solve for the constant C using your initial conditions
Thanks!
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Yw :)
Im probably going to have a lot more questions coming too I hate finals!
Haha, awesome! :P
separable are one of my fav questions
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