Can someone help me out please? I need to find out how I can the x-intercepts of the function C(x)=x^2+5x+6
set it equal to zero and solve for \(x\)
could someone show me how thats done exactly?
I got six but I'm supposed to explain how I got it do I just put in the steps I did?
\[x^2+5x+6=0\] is a start
this one factors so it is not too bad otherwise you need the quadratic formula
btw it is not 6 for sure you wil get two answers, neither are 6
Hm, should I add 5x to x^2?
oh wait
got that totally wrong, I get two x's x=-3 and x=-2
no they are not like tersm, you cannot add them you have to factor this \[(x+a)(x+b)=0\]
right?
bingo
Okai, and if its not too much, how could I construct a rough graph of it? The question I'm on really sucks. Its like "Describe how to construct a rough graph of C(x) so that the meteorologist can predict when there will be no change in the water vapor."...
it is a quadratic, meaning the shape will be a parabola since the leading coefficient is positive, ( it is 1) the parabola will open up it crosses the x axis at the two numbers you found \((-3,0)\) and \((-2,0)\)
you want a nice picture, it will look something like this http://www.wolframalpha.com/input/?i=x^2%2B5x%2B6
you can see where it crosses the x axis
Yeah i see
So is this all I need to answer this?
@satellite73
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