When solving the system of equations y equals x squared, y equals 10 minus three x algebraically, which of the following quadratic equations do you need to solve during the process?

Question

anonymous · Answer

x2 − 3x − 10 = 0

 x2 + 3x − 10 = 0

 x2 + 3x + 10 = 0

 2y = x2 − 3x + 10

anonymous · Answer

attachment

anonymous · Answer

Have any ideas?

anonymous · Answer

I think its the last one but not quite sure

anonymous · Answer

That would be incorrect because remember to solve a quadratic it's better if you have all terms on one side

anonymous · Answer

So what would this system be if you tried to solve it with substitution?

anonymous · Answer

maybe the first no clue honestly

anonymous · Answer

Ok so
y=x^2
and 
y=10-3x
So therefore since y=x^2 we can say
$$x^2=10-3x$$

anonymous · Answer

Now try and get all the terms on 1 side