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Mathematics 19 Online
OpenStudy (cutiecomittee123):

a few law of sines questions! PLEASE HELP!!!

OpenStudy (pinkpiggy):

ok, shoot

OpenStudy (pinkpiggy):

ill try my best

OpenStudy (cutiecomittee123):

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OpenStudy (pinkpiggy):

What grade?

OpenStudy (cutiecomittee123):

precalculus

OpenStudy (pinkpiggy):

ok, whats the question

OpenStudy (cutiecomittee123):

find the missing sides and angles of that triangle using law of sines

OpenStudy (pinkpiggy):

ok, give me a min

OpenStudy (anonymous):

|dw:1450148031997:dw|

OpenStudy (cutiecomittee123):

are you sure? the unit right now is just law of sines, but we can try law of cosines

OpenStudy (anonymous):

the other angle you find easily because the sum is 180

OpenStudy (anonymous):

what is the remaining angle?

OpenStudy (cutiecomittee123):

Yeah so 180-45-15=120

OpenStudy (anonymous):

you do not need the law of cosines, you have all three angles

OpenStudy (anonymous):

|dw:1450148144666:dw|

OpenStudy (cutiecomittee123):

I think I have it from here, Idk why I was confused. Let me try this and Ill tell you guys what I get

OpenStudy (anonymous):

\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] you know three of those four numbers

OpenStudy (cutiecomittee123):

so 200/sinA=x/sin45

OpenStudy (anonymous):

Angle B = 180-60 = 120 degrees a =

OpenStudy (anonymous):

no your equation is not right use the one i wrote, but put in the numbers that you know

OpenStudy (cutiecomittee123):

alright, I am officially stuck

OpenStudy (anonymous):

do you see the equation i wrote above?

OpenStudy (cutiecomittee123):

I knew the equation you gave me, I dont know which numbers to plug into it

OpenStudy (cutiecomittee123):

which one is A, and which one is A

OpenStudy (anonymous):

\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] look at the labelling of the triangle what is angle A

OpenStudy (cutiecomittee123):

B

OpenStudy (cutiecomittee123):

x/45=200/sinB

OpenStudy (anonymous):

it depends on how you label it, but you drew the picture with the angles labelled

OpenStudy (cutiecomittee123):

oops I mean x/sin45=3200/sinB

OpenStudy (anonymous):

wait hold on a second i think i see what the problem is

OpenStudy (cutiecomittee123):

ohh lol I forgot about the angle

OpenStudy (cutiecomittee123):

x/sin45=200/sin120

OpenStudy (anonymous):

in order to keep all of this striaight, we usually adopt the following convention the side opposite angle \(A\) is \(a\) , the side opposite angle \(B\) is \(b\) and opposite \(C\) is \(c\)

OpenStudy (anonymous):

that way \[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] makes sense

OpenStudy (cutiecomittee123):

Yeah so the equation I just posted should be right

OpenStudy (anonymous):

no x's in other words

OpenStudy (anonymous):

what side are you solving for?

OpenStudy (cutiecomittee123):

so then a/sin45=200/sin120

OpenStudy (anonymous):

bingo

OpenStudy (anonymous):

making \[a=\frac{200\sin(45)}{\sin(120)}\] and a calculator

OpenStudy (cutiecomittee123):

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