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OpenStudy (pinkpiggy):
ok, shoot
OpenStudy (pinkpiggy):
ill try my best
OpenStudy (cutiecomittee123):
|dw:1450147814007:dw|
OpenStudy (pinkpiggy):
What grade?
OpenStudy (cutiecomittee123):
precalculus
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OpenStudy (pinkpiggy):
ok, whats the question
OpenStudy (cutiecomittee123):
find the missing sides and angles of that triangle using law of sines
OpenStudy (pinkpiggy):
ok, give me a min
OpenStudy (anonymous):
|dw:1450148031997:dw|
OpenStudy (cutiecomittee123):
are you sure? the unit right now is just law of sines, but we can try law of cosines
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OpenStudy (anonymous):
the other angle you find easily because the sum is 180
OpenStudy (anonymous):
what is the remaining angle?
OpenStudy (cutiecomittee123):
Yeah so 180-45-15=120
OpenStudy (anonymous):
you do not need the law of cosines, you have all three angles
OpenStudy (anonymous):
|dw:1450148144666:dw|
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OpenStudy (cutiecomittee123):
I think I have it from here, Idk why I was confused. Let me try this and Ill tell you guys what I get
OpenStudy (anonymous):
\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] you know three of those four numbers
OpenStudy (cutiecomittee123):
so 200/sinA=x/sin45
OpenStudy (anonymous):
Angle B = 180-60 = 120 degrees
a =
OpenStudy (anonymous):
no your equation is not right
use the one i wrote, but put in the numbers that you know
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OpenStudy (cutiecomittee123):
alright, I am officially stuck
OpenStudy (anonymous):
do you see the equation i wrote above?
OpenStudy (cutiecomittee123):
I knew the equation you gave me, I dont know which numbers to plug into it
OpenStudy (cutiecomittee123):
which one is A, and which one is A
OpenStudy (anonymous):
\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] look at the labelling of the triangle
what is angle A
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OpenStudy (cutiecomittee123):
B
OpenStudy (cutiecomittee123):
x/45=200/sinB
OpenStudy (anonymous):
it depends on how you label it, but you drew the picture with the angles labelled
OpenStudy (cutiecomittee123):
oops I mean x/sin45=3200/sinB
OpenStudy (anonymous):
wait hold on a second
i think i see what the problem is
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OpenStudy (cutiecomittee123):
ohh lol I forgot about the angle
OpenStudy (cutiecomittee123):
x/sin45=200/sin120
OpenStudy (anonymous):
in order to keep all of this striaight, we usually adopt the following convention
the side opposite angle \(A\) is \(a\) , the side opposite angle \(B\) is \(b\) and opposite \(C\) is \(c\)
OpenStudy (anonymous):
that way \[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}\] makes sense
OpenStudy (cutiecomittee123):
Yeah so the equation I just posted should be right
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OpenStudy (anonymous):
no x's in other words
OpenStudy (anonymous):
what side are you solving for?
OpenStudy (cutiecomittee123):
so then a/sin45=200/sin120
OpenStudy (anonymous):
bingo
OpenStudy (anonymous):
making \[a=\frac{200\sin(45)}{\sin(120)}\] and a calculator
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