Law of sines question, please help me walk through it!:)
|dw:1450150179854:dw|
bet it is the same as the last one right?
very close
good work on the labeling too
so I know that we need to do 1/sin13=b/sin5 then I am confused is it b=1sin13/sin5 ?
yes
okay so b=2.58, but now how do we find c? this doesnt seem isoceles. it seems like a scalene triangle where all sides are different measures and angles too
multiply by the denominator
oh do it the same as the other one only this time use \(\sin(C)\)
so we use a/sinA=c/sinC?
yes it is the same
after all, we can move the letters around, the law of sines is just the law of sines don't get married to the variables
the length of a side divided by the sine of the opposite angle is equal to the length of any other side divided by the side of its opposite angle there is nothing magic about the \(a,b,c\)
okay well I did 1/sin13=c/sin162 but it gave me .73 and that cannot be right
1sin13/sin162^
why it is not right?
I guess it is just weird to have a decimal as a side length
oh i see hold on
So sorry about that, we had an issue in the family
it is not that it is a decimal, it is that it is smaller than one
\[\frac{1}{\sin(13)}=\frac{c}{\sin(162)}\] \[c=\frac{\sin(162)}{\sin(13)}\] you had it up side down
Which means that we have to use the thing where there are two answers dont we? you know; b1=sin^-1(b/aSinA), b2=180-sin^-1(b/aSinA)
ohhh so C goes on the top.
oh no you are finding the length of a side, not an angle
yeah \[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}\]
gotcha, well now I have c=1.37
way more accurate
yes
side opposite the largest angle is the largest side etc
okay cool
lol well I am gonna make another one again, here i go
ooooh kay
Join our real-time social learning platform and learn together with your friends!