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Just want to make sure I can do this Got the integral of e^x * e^x dx. I make u=e^x, and du has to be e^x as well. So I just use one for each, and end up with integral of u du.
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\[\int\limits e^x e^x dx\]
?
\[\int\limits\limits e^x e^x dx = \int\limits e^{2x} dx\]
u = 2x yadi yadi yada
or sub \(u = e^x\)
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oh @DurableToaster has written that already oops
yeah
why not?
i dont talk to kids with cp
hey I don't have CP just chicken pox
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but yes, not talking to people with CP is the way to go
thanks
That's strange. Couldn't I just take the whole e^x as u? Cause d/dx e^x is e^x, u=du, so I could substitute the e^xs for different things, getting e^x^2 * 1/2.... The Same as you got. Sweet!
Yes you can
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