Question

solve 5^x=3^2x-1

Answer 1

I know I have to take the ln of each side

Answer 2

What are we supposed to solve

Answer 3

Oh

Answer 4

We need to know the question to answer it

Answer 5

Lets go through some simple steps

Answer 6

I'll watch.

Answer 7

So what steps to you know about this problem

Answer 8

solve for x

Answer 9

I know

Answer 10

Ok

Answer 11

So first we need to do

Answer 12

2x
x-1=log (3 )
5

Answer 13

The answer is 2.738

Answer 14

lol okay so
1) take ln of each side ln5x=ln 3(2x-1)
2) move exponents to the front xln(5)=2x-1ln(3)
3) expand left side xln(5)=2ln(3) +xln(3)-ln(3)
4) factor out x x[ln(5) -ln(3)]

Answer 15

The answer is 2.738

Answer 16

no the answer needs to be in terms of ln

Answer 17

Oh oh ooooooooooooh

Answer 18

I still know what it is

Answer 19

Its

Answer 20

That is the answer just click that link

Answer 21

the answer is ln3/2ln3-ln5

Answer 22

Yes

Answer 23

how do u get that?

Answer 24

help me please @Zarkon

Answer 25

ln3/2ln3-ln5

Answer 26

is that what you got @denisaboichuk

Answer 27

help me plz @Nnesha

Answer 28

what do you need help with?
i mean from where to start

Answer 29

\(\color{blue}{\text{Originally Posted by}}\) @lisa123
the answer is ln3/2ln3-ln5
\(\color{blue}{\text{End of Quote}}\)
do you know wanna know how that iis the answer ?? or??

Answer 30

I already helped her

Answer 31

Look at the chat

Answer 32

yes

Answer 33

\(\color{blue}{\text{Originally Posted by}}\) @lisa123
lol okay so
1) take ln of each side ln5x=ln 3(2x-1)
2) move exponents to the front xln(5)=2x-1ln(3)
3) expand left side xln(5)=2ln(3) +xln(3)-ln(3)
4) factor out x x[ln(5) -ln(3)]
\(\color{blue}{\text{End of Quote}}\)
there is mistake or typo i guess in 3rd step

Answer 34

I meant to say expand the right side

Answer 35

\[\large\rm xln(5)=(2x-1)\ln(3)\]
(2x-1) is the exponent so you should distribute it by ln(3)
so ln(3) [(2x-1)] = ??

Answer 36

I don't know

Answer 37

familiar with the distributive property \[\rm a(b+c)=a*b+a*c=ab+ac\]multiply both terms of the parentheses by outside term

Answer 38

2xln 3 -ln3

Answer 39

yep correct
so xln(5)=2xln(3)-ln(3) now get all x terms on one side of the equal sign

Answer 40

xln 5 -2xln 3- ln3

Answer 41

no xln5-2x ln3 +ln 3

Answer 42

hmm keep the ln(3) at the right side
so -2xln(3)+xln(5)=-ln(3)
now you can take out the common factor

Answer 43

just think about simple algebra question
3x=4x-5 we should move the 4x term to the left side right in order to solve for x ?

Answer 44

oh so x(ln 5 -2 ln3)= ln 3
divide both sides
x=ln3/2ln3-ln5

Answer 45

yep right but.. what did you do to change positive ln 5 to negative and negative -2ln(3) to positive ?

Answer 46

Cause thats how the answer choice I have is written but how come the 2xln 3 doesn't separate into 2ln3+xln3

Answer 47

it's not `xln(3)`
remember \[\rm (2x-1)\ln(3) = 2x*\ln(3) -1 *\ln(3)\] so there is not x with `1 *ln(3)`

Answer 48

and also when u got \[\rm -2xln(3)+\ln(5)=-\ln(3)\]
there is a negative sign at front of 2 so take out that as well with the x varaible