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\[\lim_{x \rightarrow 0}\frac{ \int\limits_{0}^{x} \sin (2t)dt }{ \int\limits_{0}^{x} \tan (t)dt}\]
All you have to do is solve the integrals individually and then solve the limit.
well, it looks like you're integrating 0/0 so i reckon you could just differentiate under the integral with l'Hopital does that sound consistent with what you're learning right now?
Umm, yes. Got it. Thankyou, guys! :D
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