The figure below shows a square ABCD and an equilateral triangle DPC: Jake makes the chart shown below to prove that triangle APD is congruent to triangle BPC: Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° − 60° = 30° Triangles APD and BPC are congruent SAS postulate Which of the following completes Jake's proof?
u are in flvs in 10 grade
yes
u are in english2 and i can help u in geometry, i need help with 2.011
*U HAVE
Can you help me with this question.
that's is why im here and help u help me with english2 if u have it
I am a senior and i am making up my credits for geometry
I dont have it . Sorry i only hace geometry right now
@malcolmmcswain can you help me?
@mathwizzard3 can you help me
So what part do you need help with?
The second one would be because all the sides of a square are equal.
And where is the following?
Are you there?
Can you help me with this one it is asking if the figures are similar and why
No because the the two 5 and 2 are not similar because it would only make sense if it was half meaning the top for the small one would have to be 2.5
Yes; the corresponding angles are congruent. No; the corresponding angles are not congruent. Yes; the corresponding sides are proportional. No; the corresponding sides are not proportional.
D
D right?
Thank you
yup :P
No problem!
Ethan is using his compass and straightedge to complete a construction of a polygon inscribed in a circle. Which polygon is he in the process of constructing?
Do you have multiple choice answers?
Because I'm kinda stuck on this one :/
Yes A: equlaterial triangle B: square C: regular pentagon D: regular hexogon
I would say either C or D.
probably D though
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV, as shown below:
A:sss B:sas C:asa D:aas
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