1) What is the range of f(x) = -x2 + 4, if the domain is {2,0,1}? A) {0,3,5} B) {0,4,3} C) {0,4,5} D) {8,4,3} @hero @thesmartone @michele_lanio
the requested range is given by the subsequent subset of the real line: \[\huge range = \left\{ {f\left( 0 \right),\quad f\left( 1 \right),\quad f\left( 2 \right)} \right\}\]
so, we have to compute these quantities: \[\huge \begin{gathered} f\left( 0 \right) = - {\left( 0 \right)^2} + 4 = ...? \hfill \\ \hfill \\ f\left( 1 \right) = - {\left( 1 \right)^2} + 4 = ...? \hfill \\ \hfill \\ f\left( 2 \right) = - {\left( 2 \right)^2} + 4 = ...? \hfill \\ \end{gathered} \]
sooo
im still confused
what is: \(0 \cdot 0+4=...?\)
we have \(0 \cdot 0 +4=4\) so \(f(0)=-(0\cdot 0 )+4=4\) then \(y=4\) belong to the requested range now, please do the same with \(f(1)\)
belongs*
so 0,4,5
\(y=0,\;y=4\) are correct! whereas we have: \(f(1)=-(1 \cdot 1)+4=-1+4=...?\)
0,3
it si \(f(1)=3\), so the requested range is the set \(y=0\) \(y=3\) and \(y=4\) so, what is the right option?
b
that's right!
cant u help me on the next ones
ok!
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